io/router: try all handlers if a key don't match the focus ancestor tree

When a key.InputOp is focused, a key.Event is matched to it and its ancestors.
If there is no focus, every handler is matched.
This change always matches to every handler, after checking the focus and
its ancestors.

Signed-off-by: Elias Naur <mail@eliasnaur.com>

io/router/key_test.go

@@ -363,11 +363,11 @@ func TestKeyRouting(t *testing.T) {
 	r2.Queue(A, B)
 
 	// With focus, the events should traverse the branch of the hit tree
-	// containing the focused element.
+	// containing the focused element, and then every handler.
 	assertKeyEvent(t, r2.Events(&handlers[4]), false)
 	assertKeyEvent(t, r2.Events(&handlers[3]), true)
 	assertKeyEvent(t, r2.Events(&handlers[2]), false)
-	assertKeyEvent(t, r2.Events(&handlers[1]), false)
+	assertKeyEvent(t, r2.Events(&handlers[1]), false, B)
 	assertKeyEvent(t, r2.Events(&handlers[0]), false, A)
 }
 

io/router/router.go

@@ -202,6 +202,12 @@ func (q *Router) queueKeyEvent(e key.Event) {
 		n := &pq.hitTree[idx]
 		if focused {
 			idx = n.next
+			if idx == -1 {
+				// No handler found in focus ancestor tree.
+				// Try all handlers.
+				idx = len(pq.hitTree) - 1
+				focused = false
+			}
 		} else {
 			idx--
 		}